The E field strength between two charged parallel plates is the ratio of the potential difference and separation of the plates
Two parallel metal plates are separated by 3.5 cm and have a potential difference of 7.9 kV.Calculate the electric force acting on a stationary charged particle between the plates that has a charge of 2.6 × 10-15 C.
Step 1: Write down the known values
Step 2:?Calculate the electric field strength between the parallel plates
Step 3:?Write out the equation for electric force on a charged particle
F?=?QE
Step 4: Substitute electric field strength and charge into electric force equation
F?=?QE?= (2.6 × 10-15) × (2.257 × 105) = 5.87 × 10-10?N = 5.9 × 10-10?N (2 s.f.)
Remember the equation for electric field strength with V and d is only used for?parallel plates, and not for point charges (where you would use?E?=?F/Q)
Fd?=?ΔVQ
W?=?Fd
The work done on the charge depends on the electric force and the distance between the plates
W?= ΔVQ
Calculate the force needed to move an electron between two parallel plates 2 m apart with a potential difference of 400 V between them
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