Gas particles exert a pressure by constantly colliding with the walls of the container
Decreasing the volume of a gas causes an increased collision frequency of the gas particles with the container wall
Three graphs that show Boyle’s Law
Increasing the temperature of a gas causes an increased collision frequency of the gas particles with the container wall (a); volume is directly proportional to the temperature in Kelvin (b)
Increasing the temperature of a gas causes an increased collision frequency of the gas particles with the container wall (a); temperature is directly proportional to the pressure (b)
At 25?oC and 100 kPa a gas occupies a volume of 20 dm3. Calculate the new temperature, in?oC, of the gas if the volume is decreased to 10 dm3 at constant pressure.
Answer:
Step 1: Rearrange the formula to change the conditions of a fixed amount of gas. Pressure is constant so it is left out of the formula
Step 2: Convert the temperature to Kelvin. There is no need to convert the volume to m3??because the formula is using a?ratio?of the two volumes
V1?= 20 dm3?
V2?= 10 dm3?
T1?= 25 + 273 = 298 K
Step 3: Calculate the new temperature
A 2.00 dm3?container of oxygen at a pressure of 80 kPa was heated from 20?oC to 70?oC The volume expanded to 2.25 dm3?. What was the final pressure of the gas?
Answer:
Step 1: Rearrange the formula to change the conditions of a fixed amount of gas
Step 2: Substitute in the values and calculate the final pressure
P1?= 80 kPa
V1?= 2.00 dm3?
V2?= 2.25 dm3?
T1?= 20 + 273 = 293 K
T2?= 70 + 273 = 343 K
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