ΔHIE1?Al (g) → Al+?(g) + e–? ? ? ? ? ΔHIE1??= +577 kJ mol-1
ΔHIE2?Al+?(g) → Al2+?(g) + e–? ? ? ΔHIE2??= +1820 kJ mol-1
Na (s) → Na (g)? ? ? ? ? ?ΔHat??= +108 kJ mol?-1
?Cl (g) → Cl (g)? ? ? ? ? ΔHat??= +122 kJ mol?-1
Cl?(g)+ e–?→ Cl–?(g) ? ? ? ? ?ΔHEA??= -364 kJ mol-1
O–?(g) + e–?→ O2-?(g) ? ? ? ? ?ΔHEA??= +844 kJ mol-1
NaCl (s) → Na+?(g) + Cl-?(g)? ? ?ΔHlat??= +790 kJ mol -1
LiBr(s) → LiBr(aq)? ? ΔHsol??= -48.8 kJ mol?-1
KCl (s) → KCI (aq)? ? ? ΔHsol??= +17.2 kJ mol?-1
CaCl2(s) → CaCl2?(aq)? ? ? ?ΔHsol??= -82.8 kJ mol?-1
Mg2+?(g) → Mg2+?(aq)? ?ΔHhyd??= -1963 kJ mol?-1
Br-?(g) → Br-?(aq)? ? ? ? ? ΔHhyd??= -328 kJ mol?-1
The polar water molecules will form ion-dipole bonds with the ions in solution causing the ions to become hydrated?
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