A + B → C + D
Elementary step 1: A → R + D
Elementary step 2: R + B → C
A + R?+ B → R + C + D
A + B → C + D
Sulfur dioxide reacts with oxygen to form sulfur trioxide
Answers
Answer 1:
Answer 2:
Elementary step 1: 2NO + O2?→ 2NO2
Elementary step 2: NO2?+ SO2?→ NO + SO3?(or 2NO2?+ 2SO2?→ 2NO + 2SO3)
It is important that you check that the equations you are proposing for a reaction mechanism. They?must add up to the overall stoichiometric equation, otherwise?the proposed mechanism is wrong.
NO2?(g) + CO (g) → NO (g) + CO2?(g)
Rate =?k?[NO2]2
Step 1:
? ?2NO2?(g) → NO (g) + NO3?(g)? ? ? ? ? ? ? ? ? ?slow?(rate-determining step)
Step 2:
? ?NO3?(g) + CO (g) → NO2?(g) + CO2?(g)? ? ?fast
Overall:
?2NO2?(g) +?NO3?(g)?+ CO (g) → NO (g) +?NO3?(g)?+?NO2?(g)?+ CO2?(g)
? ?=? ? ?NO2?(g) + CO (g) → NO (g) + CO2?(g)
It is important that the elementary steps for a proposed mechanism also agree with the experimentally determined rate equation. The rate equation and the overall reaction must be related, i.e. the correct chemical species involved.?Remember: There is no direct link between the orders in the rate equation and the stoichiometry of the overall equation. However, the rate equation can be derived directly from the rate determining step and its stoichiometry
2NO (g) + 2H2?(g) → N2?(g) + 2H2O (l)
Step 1:
? ?NO (g) + NO (g) → N2O2?(g)? ? ? ? ? ? ? ? ? ? ??fast
Step 2:
? ?N2O2?(g) + H2?(g) → H2O (l) + N2O (g)??? ?slow?(rate-determining step)
Step 3:
? ?N2O (g) + H2?(g) → N2?(g) + H2O (l)? ? ? ? ? ?fast
Rate =?k?[NO]2?[H2]
Intermediates in the mechanism?cannot?appear as substances in the rate equationThis is why you substitute the N2O2?in the above example. Step 1 shows that 2NO molecules are required to form the necessary N2O2
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