Phase changes for water
The graph below is the heating curve for a 25 g cube of ice being heated at a constant rate. Calculate:
Step 1: Write down the mass?m?of ice in kilograms (kg)
m?= 25 g = 0.025 kg
Step 2:? Read from the graph the amount of energy?E1?being supplied to the water in its liquid phase as it warms up
E1?= 20 kJ – 10 kJ = 10 kJ
Step 3: Convert this energy from kilojoules into joules?
E1?= 10 kJ = 10000 J
Step 4:? Read from the graph the change in temperature?ΔT1?of the water as it warms up
ΔT1?= 100°C – 0°C = 100°C
Step 5: Write down the equation linking thermal energy?E1?to mass?m, specific heat capacity?c?and change in temperature?ΔT1
E1?=?mcΔT1
Step 6: Solve for the specific heat capacity?c
c?= 4000 J kg–1?°C–1
Step 7: Read from the graph the amount of energy?E2?being supplied to the water as it changes into a gas at 100°C
E2= 56 kJ = 56000 J
Step 8: Write down the equation linking thermal energy?E2?to mass?m?and specific latent heat of vaporisation?Lv
E2?=?mLv
Step 9: Solve for the specific latent heat of fusion?Lv
Lv?= 2.2 × 106?J kg–1
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