Br2(l) + 2e-?? 2Br-(aq)? ? ? ? voltage = +1.09 V
Na+(aq) + e-?? Na(s)? ? ? ? voltage = -2.71 V
Br2(l) + 2e-?? 2Br-(aq)? ? ? ??E??= +1.09 V
2H+(aq) + 2e-?? H2(g)? ? ? ??E??= 0.00 V
Na+?(aq) + e-?? Na(s)? ? ? ??E??= -2.71 V
2H+?(aq) + 2e-?? H2(g)? ? ? ??E??= 0.00 V
Ecell??= (+1.09) - (-2.71)
= +3.80 V
Cu(s) → Cu2+(aq) + 2e-
Oxidation of copper ions
Cu2+(aq) + 2e-?→ Cu(s)
Reduction of copper ions
Cu2+?(aq) + 2e-?? Cu (s)
V2+?(aq) + 2e-?? V(s)
2H+?(aq) + 2e-?? H2?(g)
The standard electrode potential of a half-cell can be determined by connecting it to a standard hydrogen electrode
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