Answer
PbBr2?(s) ? Pb2+?(aq) + 2Br-?(aq)
Ksp?= [Pb2+(aq)] [Br-?(aq)]2
[PbBr2(s)] = 1.39 x 10-3?mol dm-3
The ratio of PbBr2?to Pb2+?is 1:1
[Pb2+(aq)] = [PbBr2(s)] = 1.39 x 10-3?mol dm-3
The ratio of PbBr2?to Br-?is 1:2
[Br-(aq)] = 2 x [PbBr2(s)] = 2 x 1.39 x 10-3?mol dm-3
= 2.78 x 10-3?mol dm-3
Ksp?= (1.39 x 10-3) x (2.78 x 10-3)2
= 1.07 x 10-8
Ksp?= (mol dm-3) x (mol dm-3)2
= mol3?dm-9
The solubility product is therefore 1.07 x 10-8?mol3?dm-9
Answer
CuO (s) ? Cu2+?(aq) + O2-?(aq)
Ksp?= [Cu2+?(aq)] [O2-?(aq)]
The ratio of Cu2+?to O2-?is 1:1
[Cu2+(aq)] = [O2-(aq)]?so the expression can be simplified to:
Ksp?= [Cu2+?(aq)]2
5.9 x 10-36?= [Cu2+?(aq)]2
= 2.4 x 10-18?mol dm-3
Since [CuO(s)] = [Cu2+?(aq)] the solubility of copper oxide is 2.4 x 10-18?mol dm-3
Remember that the solubility product is only applicable to very slightly soluble salts and cannot be used for soluble salts such as:
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